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An Introduction to Statistics

Odd Solution for Statistics Lesson 7

  1. Graduating Math and Science Center students have a mean ACT score of 29. Calculate the z-score for their mean relative to the national mean of 21.0 and standard deviation of 4.7.
    (29-21)/4.7 = 1.70

  2. Given the fact that 50% of a normally distributed data set is within 0.675 standard deviations of the mean, estimate Q1, Q3, and the interquartile range for Center Senior ACT scores, given also a mean of 29 and standard deviation of 3.0. Would an ACT score of 36 be unusual for a Center student?
    z=±0.675 = (x - 29)/3.0       x = 26.975 or 31.025
    Q1=27.0   Q3=31.0   Q3 - Q1 = 31.0 - 27.0 = 4.0
    29 + 2s = 29 + 6.0 = 35.0 < 36, so yes.
    New info: mean = 28.3; s=2.6; 3 35's known.

  3. Calculate the z-score for the largest value in the above data set. Is it an ordinary score? Is it an outlier? Which definition works best?
    z = (360,000,000 - 66400)/373000 = 965.00!
    It is VERY unusual data value (outlier).
    The hinge and quartile definitions fail!

  4. Using the data set: {0, 2, 4, 5, 6, 3, 6, 1, 1, 50}, as given in the lesson, calculate its 5-number summary, using the quartiles.
    minX=0   Q1=1   Median=3.5   Q3=6   maxX=50

  5. Using the fifty 1999 class of 2003 Algebra Diagnostic Test scores: 140, 122, 119, 99, 92, 90, 90, 88, 85, 82, 82, 81, 80, 80, 77, 74, 74, 73, 72, 71, 70, 70, 69, 69, 69, 68, 68, 68, 67, 66, 64, 64, 62, 60, 59, 59, 58, 58, 56, 56, 56, 56, 55, 54, 53, 53, 50, 47, 35, 32, find P10, P90 and the 10-90 percentile range. Show all your work.
    L10 = (10/100)(50) = 5           (53 + 53)/2 = 53 = P10
    L90 = (90/100)(50) = 45       (90+92)/2 = 91.0 = P90
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